Optimal. Leaf size=382 \[ \frac {b^2 f^2 x}{3 d^2}-\frac {2 a b f (d e-c f) x}{d^2}-\frac {b^2 f^2 \text {ArcTan}(c+d x)}{3 d^3}-\frac {2 b^2 f (d e-c f) (c+d x) \text {ArcTan}(c+d x)}{d^3}-\frac {b f^2 (c+d x)^2 (a+b \text {ArcTan}(c+d x))}{3 d^3}+\frac {i \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) (a+b \text {ArcTan}(c+d x))^2}{3 d^3}-\frac {(d e-c f) \left (d^2 e^2-2 c d e f-\left (3-c^2\right ) f^2\right ) (a+b \text {ArcTan}(c+d x))^2}{3 d^3 f}+\frac {(e+f x)^3 (a+b \text {ArcTan}(c+d x))^2}{3 f}+\frac {2 b \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) (a+b \text {ArcTan}(c+d x)) \log \left (\frac {2}{1+i (c+d x)}\right )}{3 d^3}+\frac {b^2 f (d e-c f) \log \left (1+(c+d x)^2\right )}{d^3}+\frac {i b^2 \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \text {PolyLog}\left (2,1-\frac {2}{1+i (c+d x)}\right )}{3 d^3} \]
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Rubi [A]
time = 0.43, antiderivative size = 382, normalized size of antiderivative = 1.00, number
of steps used = 16, number of rules used = 13, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.650, Rules
used = {5155, 4974, 4930, 266, 4946, 327, 209, 5104, 5004, 5040, 4964, 2449, 2352}
\begin {gather*} \frac {i \left (-\left (1-3 c^2\right ) f^2-6 c d e f+3 d^2 e^2\right ) (a+b \text {ArcTan}(c+d x))^2}{3 d^3}-\frac {(d e-c f) \left (-\left (3-c^2\right ) f^2-2 c d e f+d^2 e^2\right ) (a+b \text {ArcTan}(c+d x))^2}{3 d^3 f}+\frac {2 b \left (-\left (1-3 c^2\right ) f^2-6 c d e f+3 d^2 e^2\right ) \log \left (\frac {2}{1+i (c+d x)}\right ) (a+b \text {ArcTan}(c+d x))}{3 d^3}-\frac {b f^2 (c+d x)^2 (a+b \text {ArcTan}(c+d x))}{3 d^3}+\frac {(e+f x)^3 (a+b \text {ArcTan}(c+d x))^2}{3 f}-\frac {2 a b f x (d e-c f)}{d^2}-\frac {2 b^2 f (c+d x) \text {ArcTan}(c+d x) (d e-c f)}{d^3}-\frac {b^2 f^2 \text {ArcTan}(c+d x)}{3 d^3}+\frac {i b^2 \left (-\left (1-3 c^2\right ) f^2-6 c d e f+3 d^2 e^2\right ) \text {Li}_2\left (1-\frac {2}{i (c+d x)+1}\right )}{3 d^3}+\frac {b^2 f (d e-c f) \log \left ((c+d x)^2+1\right )}{d^3}+\frac {b^2 f^2 x}{3 d^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 209
Rule 266
Rule 327
Rule 2352
Rule 2449
Rule 4930
Rule 4946
Rule 4964
Rule 4974
Rule 5004
Rule 5040
Rule 5104
Rule 5155
Rubi steps
\begin {align*} \int (e+f x)^2 \left (a+b \tan ^{-1}(c+d x)\right )^2 \, dx &=\frac {\text {Subst}\left (\int \left (\frac {d e-c f}{d}+\frac {f x}{d}\right )^2 \left (a+b \tan ^{-1}(x)\right )^2 \, dx,x,c+d x\right )}{d}\\ &=\frac {(e+f x)^3 \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 f}-\frac {(2 b) \text {Subst}\left (\int \left (\frac {3 f^2 (d e-c f) \left (a+b \tan ^{-1}(x)\right )}{d^3}+\frac {f^3 x \left (a+b \tan ^{-1}(x)\right )}{d^3}+\frac {\left ((d e-c f) \left (d^2 e^2-2 c d e f-3 f^2+c^2 f^2\right )+f \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) x\right ) \left (a+b \tan ^{-1}(x)\right )}{d^3 \left (1+x^2\right )}\right ) \, dx,x,c+d x\right )}{3 f}\\ &=\frac {(e+f x)^3 \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 f}-\frac {(2 b) \text {Subst}\left (\int \frac {\left ((d e-c f) \left (d^2 e^2-2 c d e f-3 f^2+c^2 f^2\right )+f \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) x\right ) \left (a+b \tan ^{-1}(x)\right )}{1+x^2} \, dx,x,c+d x\right )}{3 d^3 f}-\frac {\left (2 b f^2\right ) \text {Subst}\left (\int x \left (a+b \tan ^{-1}(x)\right ) \, dx,x,c+d x\right )}{3 d^3}-\frac {(2 b f (d e-c f)) \text {Subst}\left (\int \left (a+b \tan ^{-1}(x)\right ) \, dx,x,c+d x\right )}{d^3}\\ &=-\frac {2 a b f (d e-c f) x}{d^2}-\frac {b f^2 (c+d x)^2 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d^3}+\frac {(e+f x)^3 \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 f}-\frac {(2 b) \text {Subst}\left (\int \left (\frac {(d e-c f) \left (d^2 e^2-2 c d e f-\left (3-c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(x)\right )}{1+x^2}+\frac {f \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) x \left (a+b \tan ^{-1}(x)\right )}{1+x^2}\right ) \, dx,x,c+d x\right )}{3 d^3 f}+\frac {\left (b^2 f^2\right ) \text {Subst}\left (\int \frac {x^2}{1+x^2} \, dx,x,c+d x\right )}{3 d^3}-\frac {\left (2 b^2 f (d e-c f)\right ) \text {Subst}\left (\int \tan ^{-1}(x) \, dx,x,c+d x\right )}{d^3}\\ &=\frac {b^2 f^2 x}{3 d^2}-\frac {2 a b f (d e-c f) x}{d^2}-\frac {2 b^2 f (d e-c f) (c+d x) \tan ^{-1}(c+d x)}{d^3}-\frac {b f^2 (c+d x)^2 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d^3}+\frac {(e+f x)^3 \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 f}-\frac {\left (b^2 f^2\right ) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,c+d x\right )}{3 d^3}+\frac {\left (2 b^2 f (d e-c f)\right ) \text {Subst}\left (\int \frac {x}{1+x^2} \, dx,x,c+d x\right )}{d^3}-\frac {\left (2 b \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right )\right ) \text {Subst}\left (\int \frac {x \left (a+b \tan ^{-1}(x)\right )}{1+x^2} \, dx,x,c+d x\right )}{3 d^3}-\frac {\left (2 b (d e-c f) \left (d^2 e^2-2 c d e f-\left (3-c^2\right ) f^2\right )\right ) \text {Subst}\left (\int \frac {a+b \tan ^{-1}(x)}{1+x^2} \, dx,x,c+d x\right )}{3 d^3 f}\\ &=\frac {b^2 f^2 x}{3 d^2}-\frac {2 a b f (d e-c f) x}{d^2}-\frac {b^2 f^2 \tan ^{-1}(c+d x)}{3 d^3}-\frac {2 b^2 f (d e-c f) (c+d x) \tan ^{-1}(c+d x)}{d^3}-\frac {b f^2 (c+d x)^2 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d^3}+\frac {i \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 d^3}-\frac {(d e-c f) \left (d^2 e^2-2 c d e f-\left (3-c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 d^3 f}+\frac {(e+f x)^3 \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 f}+\frac {b^2 f (d e-c f) \log \left (1+(c+d x)^2\right )}{d^3}+\frac {\left (2 b \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right )\right ) \text {Subst}\left (\int \frac {a+b \tan ^{-1}(x)}{i-x} \, dx,x,c+d x\right )}{3 d^3}\\ &=\frac {b^2 f^2 x}{3 d^2}-\frac {2 a b f (d e-c f) x}{d^2}-\frac {b^2 f^2 \tan ^{-1}(c+d x)}{3 d^3}-\frac {2 b^2 f (d e-c f) (c+d x) \tan ^{-1}(c+d x)}{d^3}-\frac {b f^2 (c+d x)^2 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d^3}+\frac {i \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 d^3}-\frac {(d e-c f) \left (d^2 e^2-2 c d e f-\left (3-c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 d^3 f}+\frac {(e+f x)^3 \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 f}+\frac {2 b \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right ) \log \left (\frac {2}{1+i (c+d x)}\right )}{3 d^3}+\frac {b^2 f (d e-c f) \log \left (1+(c+d x)^2\right )}{d^3}-\frac {\left (2 b^2 \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right )\right ) \text {Subst}\left (\int \frac {\log \left (\frac {2}{1+i x}\right )}{1+x^2} \, dx,x,c+d x\right )}{3 d^3}\\ &=\frac {b^2 f^2 x}{3 d^2}-\frac {2 a b f (d e-c f) x}{d^2}-\frac {b^2 f^2 \tan ^{-1}(c+d x)}{3 d^3}-\frac {2 b^2 f (d e-c f) (c+d x) \tan ^{-1}(c+d x)}{d^3}-\frac {b f^2 (c+d x)^2 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d^3}+\frac {i \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 d^3}-\frac {(d e-c f) \left (d^2 e^2-2 c d e f-\left (3-c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 d^3 f}+\frac {(e+f x)^3 \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 f}+\frac {2 b \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right ) \log \left (\frac {2}{1+i (c+d x)}\right )}{3 d^3}+\frac {b^2 f (d e-c f) \log \left (1+(c+d x)^2\right )}{d^3}+\frac {\left (2 i b^2 \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right )\right ) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+i (c+d x)}\right )}{3 d^3}\\ &=\frac {b^2 f^2 x}{3 d^2}-\frac {2 a b f (d e-c f) x}{d^2}-\frac {b^2 f^2 \tan ^{-1}(c+d x)}{3 d^3}-\frac {2 b^2 f (d e-c f) (c+d x) \tan ^{-1}(c+d x)}{d^3}-\frac {b f^2 (c+d x)^2 \left (a+b \tan ^{-1}(c+d x)\right )}{3 d^3}+\frac {i \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 d^3}-\frac {(d e-c f) \left (d^2 e^2-2 c d e f-\left (3-c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 d^3 f}+\frac {(e+f x)^3 \left (a+b \tan ^{-1}(c+d x)\right )^2}{3 f}+\frac {2 b \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \left (a+b \tan ^{-1}(c+d x)\right ) \log \left (\frac {2}{1+i (c+d x)}\right )}{3 d^3}+\frac {b^2 f (d e-c f) \log \left (1+(c+d x)^2\right )}{d^3}+\frac {i b^2 \left (3 d^2 e^2-6 c d e f-\left (1-3 c^2\right ) f^2\right ) \text {Li}_2\left (1-\frac {2}{1+i (c+d x)}\right )}{3 d^3}\\ \end {align*}
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Mathematica [B] Both result and optimal contain complex but leaf count is larger than twice
the leaf count of optimal. \(801\) vs. \(2(382)=764\).
time = 2.66, size = 801, normalized size = 2.10 \begin {gather*} a^2 e^2 x+a^2 e f x^2+\frac {1}{3} a^2 f^2 x^3+\frac {a b \left (-d f x (6 d e-4 c f+d f x)+2 \left (3 d e f-3 c^2 d e f+c^3 f^2+3 c \left (d^2 e^2-f^2\right )+d^3 x \left (3 e^2+3 e f x+f^2 x^2\right )\right ) \text {ArcTan}(c+d x)+\left (-3 d^2 e^2+6 c d e f+\left (1-3 c^2\right ) f^2\right ) \log \left (1+(c+d x)^2\right )\right )}{3 d^3}+\frac {b^2 e^2 \left (\text {ArcTan}(c+d x) \left ((-i+c+d x) \text {ArcTan}(c+d x)+2 \log \left (1+e^{2 i \text {ArcTan}(c+d x)}\right )\right )-i \text {PolyLog}\left (2,-e^{2 i \text {ArcTan}(c+d x)}\right )\right )}{d}+\frac {b^2 e f \left (\left (1+2 i c-c^2+d^2 x^2\right ) \text {ArcTan}(c+d x)^2-2 \text {ArcTan}(c+d x) \left (c+d x+2 c \log \left (1+e^{2 i \text {ArcTan}(c+d x)}\right )\right )+\log \left (1+(c+d x)^2\right )+2 i c \text {PolyLog}\left (2,-e^{2 i \text {ArcTan}(c+d x)}\right )\right )}{d^2}+\frac {b^2 f^2 \left (1+(c+d x)^2\right )^{3/2} \left (\frac {c+d x}{\sqrt {1+(c+d x)^2}}+\frac {6 c (c+d x) \text {ArcTan}(c+d x)}{\sqrt {1+(c+d x)^2}}+\frac {3 (c+d x) \text {ArcTan}(c+d x)^2}{\sqrt {1+(c+d x)^2}}+\frac {3 c^2 (c+d x) \text {ArcTan}(c+d x)^2}{\sqrt {1+(c+d x)^2}}+i \text {ArcTan}(c+d x)^2 \cos (3 \text {ArcTan}(c+d x))-3 i c^2 \text {ArcTan}(c+d x)^2 \cos (3 \text {ArcTan}(c+d x))-2 \text {ArcTan}(c+d x) \cos (3 \text {ArcTan}(c+d x)) \log \left (1+e^{2 i \text {ArcTan}(c+d x)}\right )+6 c^2 \text {ArcTan}(c+d x) \cos (3 \text {ArcTan}(c+d x)) \log \left (1+e^{2 i \text {ArcTan}(c+d x)}\right )+6 c \cos (3 \text {ArcTan}(c+d x)) \log \left (\frac {1}{\sqrt {1+(c+d x)^2}}\right )+\frac {\left (3 i-12 c-9 i c^2\right ) \text {ArcTan}(c+d x)^2+2 \text {ArcTan}(c+d x) \left (-2+\left (-3+9 c^2\right ) \log \left (1+e^{2 i \text {ArcTan}(c+d x)}\right )\right )+18 c \log \left (\frac {1}{\sqrt {1+(c+d x)^2}}\right )}{\sqrt {1+(c+d x)^2}}-\frac {4 i \left (-1+3 c^2\right ) \text {PolyLog}\left (2,-e^{2 i \text {ArcTan}(c+d x)}\right )}{\left (1+(c+d x)^2\right )^{3/2}}+\sin (3 \text {ArcTan}(c+d x))+6 c \text {ArcTan}(c+d x) \sin (3 \text {ArcTan}(c+d x))-\text {ArcTan}(c+d x)^2 \sin (3 \text {ArcTan}(c+d x))+3 c^2 \text {ArcTan}(c+d x)^2 \sin (3 \text {ArcTan}(c+d x))\right )}{12 d^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 1607 vs. \(2 (362 ) = 724\).
time = 0.43, size = 1608, normalized size = 4.21
method | result | size |
derivativedivides | \(\text {Expression too large to display}\) | \(1608\) |
default | \(\text {Expression too large to display}\) | \(1608\) |
risch | \(\text {Expression too large to display}\) | \(2653\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (a + b \operatorname {atan}{\left (c + d x \right )}\right )^{2} \left (e + f x\right )^{2}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (e+f\,x\right )}^2\,{\left (a+b\,\mathrm {atan}\left (c+d\,x\right )\right )}^2 \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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